Student's Name: PLEASE INSERT YOUR NAME HERE (DOUBLE CLICK THIS BOX TO EDIT.)
Directions: Add work to this notebook to solve the problems below.
Problem Sources:
These are standard imports:
import numpy as np
import math as m
import matplotlib.pyplot as plt
1: Volume of a cube
Set the variable V
to be the volume (in $cm^3$) of a cube whose side length is L=4 cm
. (This is a modification of Exercises 1.2 from LL § 1.9.)
L = 4 # Side length is 4 cm
2: Circumference and area of a circle
Complete the following functions which compute the circumference and area of a circle given its radius. Replace the ???
with the correct expressions. Test your code to make sure it is working by running the code below. (This is a modification of Exercises 1.3 from LL § 1.9.)
def circumference(radius):
return ???
def area(radius):
return ???
circumference(1)
circumference(0.5)
area(1)
area(2)
This is problem 1.4 of LL § 1.9:
Read section 1.6.2 of of LL about printing in Python, and use what you have learned to complete problem 1.6 of LL:
Write your solution below:
Let $p$ be a bank’s interest rate in percent per year. An initial amount $A$ has then grown to
$$A(1+\frac{p}{100})^n$$
after $n$ years. Write a function compute_new_amount
that takes as input three variables A
, p
, and n
as above and outputs the result of the formula above. Use it to compute how much money 1000
euros have grown to after three years with 5% interest rate.
(This is a modification of Exercise 1.5 of L.)
def compute_new_amount(A, p, n):
return ???
compute_new_amount(1000, 5, 3)
Suppose somebody has written a simple one-line program for computing sin(1):
x=1; print 'sin(%g)=%g' % (x, sin(x))
Fix this program so that it runs correctly.
(This is a modification of Exercise 1.6 of L.)
x=1; print('sin(%g)=%g' % (x, sin(x)))
Attempt to execute these short programs. When they do not work, identify and correct the erroneous statements.
(This is exercise 1.8 from L.)
Does $sin^2(x) + cos^2(x) = 1$?
from math import sin, cos
x = pi/4
1_val = sin^2(x) + cos^2(x)
print 1_VAL
Work with the expressions for movement with constant acceleration:
v0 = 3 m/s
t = 1 s
a = 2 m/s**2
s = v0*t + 1/2 a*t**2
print(s)
Verify these equations: $$(a+b)^2 = a^2 + 2ab+b^2,$$ $$(a-b)^2 = a^2-2ab+b^2.$$
a = 3.3
b = 5.3
a2 = a**2
b2 = b**2
eq1_sum = a2 + 2ab + b2
eq2_sum = a2 - 2ab + b2
eq1_pow = (a + b)**2
eq2_pow = (a - b)**2
print 'First equation: %g = %g', % (eq1_sum, eq1_pow)
print 'Second equation: %h = %h', % (eq2_pow, eq2_pow)
(This is a modification of problem 1.9 of L.)
The following is an attempt at an implementation of the quadratic formula, returning the pair of solutions to $a x^2+bx+c = 0$. Recall that the roots have the form $$x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}.$$
from math import sqrt
def roots(a, b, c):
q = sqrt(b*b - 4*a*c)
root1 = (-b + q)/2*a
root2 = (-b - q)/2*a
return (root1, root2)
Note that
$$(2 x-1)(x-2)=2 x^2 - 5x +2.$$
Thus roots(2, -5, 2)
should return the pair (2, 0.5)
(since the biggest root is returned first if a>0
). But it currently doesn't work:
roots(2, -5, 2)
Correct the roots
function above so that it works correctly.